Solving Massless Pulley: Finding Accelerations, Tension & Pulley Motion

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SUMMARY

The forum discussion centers on solving a physics problem involving a massless pulley system with two unequal masses, m1 and m2, connected by a massless string. The external force F is applied to the pulley, and the challenge is to determine the accelerations of each mass, the tension in the string, and the motion of the pulley. Key equations include F = ma, and the discussion emphasizes the importance of considering two reference frames to analyze the system effectively.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Familiarity with concepts of acceleration and tension in pulley systems
  • Knowledge of reference frames in physics
  • Ability to perform algebraic manipulations for solving equations
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  • Study the dynamics of pulley systems with unequal masses
  • Learn how to apply Newton's laws in different reference frames
  • Explore the concept of center of mass and its relevance in mechanics
  • Practice solving problems involving tension and acceleration in multi-body systems
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking for insights into teaching pulley dynamics and problem-solving strategies.

tonicandgin
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Homework Statement



m1 and m2 are connected by a massless string wrapped around a massless pulley. An external force F is applied to the pulley. m1 does not equal m2

find the acceleration of each mass, the tension in the string, and the acceleration of the pulley.

F external and m1 and m2 are known.

there is no gravity or friction in the problem.

Homework Equations



F=ma



The Attempt at a Solution



What I've worked out so far is that we must consider two reference frames to determine the accelerations. If we can calculate the acceleration of the pulley and the acceleration of one of the masses, the acceleration of the other mass should be determined.

If we consider the pulley's reference frame, one of the masses will be accelerating toward the pulley and the other mass will be accelerating with an equal and opposite acceleration.

If we consider m1, we see the pulley accelerating toward m1 and m2 accelerating with an equal acceleration.

how can we combine these two reference frames to determine the accelerations in the lab frame?

is the acceleration of the center of mass of the system relevant?
 
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welcome to pf!

hi tonicandgin! welcome to pf! :wink:
tonicandgin said:
… we must consider two reference frames …

no :confused:

call the position of the pulley x, call the length of string between the pulley and m1 and m2, respectively, L1 and L2

and use the fact that L1 + L2 must be constant …

what do you get? :smile:
 


thanks for the response.

to clarify: what do you mean by "call the position of the pulley x"? is that its position before the force is applied and everything starts moving? or does x change as the system moves?


what i have so far is:

call position of the pulley x. call the length between pulley and the 2 masses L1 and L2, respectively
then position of m1 = x - L1 + 1/2 am1t2
and position of m2 = x - L2 + 1/2 am2t2

i've done a bunch of algebra trying to make use of L1 + L2 = L but nothing seems useful.

I think what i should do is write position equations for each mass and then take two time derivatives to get acceleration, but the only position equations i can write include the accelerations I'm looking for in the first place.
 
hi tonicandgin! :smile:

(just got up :zzz: …)
tonicandgin said:
… does x change as the system moves?

yes, that's the easiest way …

then you get …

position of m1 = x - L1
position of m2 = x - L2

then call the tension T, and do F = ma for each mass separately …

what do you get? :smile:
 


thanks for the help. so far I have:

a1 - ar = ap
a2 + ar = ap

where ar is the relative acceleration of each mass with the pulley.

( m1x1 + m2x2 ) / ( m1 + m2 ) is the center of mass of the system. if we take two time derivatives we get ( m1a1 + m2a2 ) / ( m1 + m2 ) which must equal the only external force, F.

F must = 2T

this is as much as i could get out of my professor today, he seemed to think it was solvable from here, but i still feel like there are too many unknowns and not enough equations.
 
hi tonicandgin! :smile:

(just got up :zzz: …)

yes, there are two ways doing it

your can either start with F = ma for the centre of mass, as your professor suggests,

or you can just do F = ma for each of the three bodies separately
tonicandgin said:
… i still feel like there are too many unknowns and not enough equations.

whichever method you choose, write out all the equations you have, and we'll see :smile:
 

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