Solving Massless Pulley: Finding Accelerations, Tension & Pulley Motion

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Homework Help Overview

The problem involves two masses connected by a massless string over a massless pulley, with an external force applied to the pulley. The objective is to find the accelerations of the masses, the tension in the string, and the acceleration of the pulley, under the conditions that there is no gravity or friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to consider multiple reference frames to analyze the system's motion. Questions arise about the relevance of the center of mass and how to combine the reference frames to determine the accelerations. There is also a focus on the relationship between the positions of the pulley and the masses, and how to express these in terms of known variables.

Discussion Status

Some participants have provided guidance on setting up equations based on the positions of the pulley and masses, while others express uncertainty about the number of unknowns relative to the equations available. The discussion is ongoing, with various methods being considered for approaching the problem.

Contextual Notes

Participants note the challenge of deriving equations due to the presence of multiple unknowns and the constraints of the problem setup, including the lack of gravitational forces and friction.

tonicandgin
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Homework Statement



m1 and m2 are connected by a massless string wrapped around a massless pulley. An external force F is applied to the pulley. m1 does not equal m2

find the acceleration of each mass, the tension in the string, and the acceleration of the pulley.

F external and m1 and m2 are known.

there is no gravity or friction in the problem.

Homework Equations



F=ma



The Attempt at a Solution



What I've worked out so far is that we must consider two reference frames to determine the accelerations. If we can calculate the acceleration of the pulley and the acceleration of one of the masses, the acceleration of the other mass should be determined.

If we consider the pulley's reference frame, one of the masses will be accelerating toward the pulley and the other mass will be accelerating with an equal and opposite acceleration.

If we consider m1, we see the pulley accelerating toward m1 and m2 accelerating with an equal acceleration.

how can we combine these two reference frames to determine the accelerations in the lab frame?

is the acceleration of the center of mass of the system relevant?
 
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welcome to pf!

hi tonicandgin! welcome to pf! :wink:
tonicandgin said:
… we must consider two reference frames …

no :confused:

call the position of the pulley x, call the length of string between the pulley and m1 and m2, respectively, L1 and L2

and use the fact that L1 + L2 must be constant …

what do you get? :smile:
 


thanks for the response.

to clarify: what do you mean by "call the position of the pulley x"? is that its position before the force is applied and everything starts moving? or does x change as the system moves?


what i have so far is:

call position of the pulley x. call the length between pulley and the 2 masses L1 and L2, respectively
then position of m1 = x - L1 + 1/2 am1t2
and position of m2 = x - L2 + 1/2 am2t2

i've done a bunch of algebra trying to make use of L1 + L2 = L but nothing seems useful.

I think what i should do is write position equations for each mass and then take two time derivatives to get acceleration, but the only position equations i can write include the accelerations I'm looking for in the first place.
 
hi tonicandgin! :smile:

(just got up :zzz: …)
tonicandgin said:
… does x change as the system moves?

yes, that's the easiest way …

then you get …

position of m1 = x - L1
position of m2 = x - L2

then call the tension T, and do F = ma for each mass separately …

what do you get? :smile:
 


thanks for the help. so far I have:

a1 - ar = ap
a2 + ar = ap

where ar is the relative acceleration of each mass with the pulley.

( m1x1 + m2x2 ) / ( m1 + m2 ) is the center of mass of the system. if we take two time derivatives we get ( m1a1 + m2a2 ) / ( m1 + m2 ) which must equal the only external force, F.

F must = 2T

this is as much as i could get out of my professor today, he seemed to think it was solvable from here, but i still feel like there are too many unknowns and not enough equations.
 
hi tonicandgin! :smile:

(just got up :zzz: …)

yes, there are two ways doing it

your can either start with F = ma for the centre of mass, as your professor suggests,

or you can just do F = ma for each of the three bodies separately
tonicandgin said:
… i still feel like there are too many unknowns and not enough equations.

whichever method you choose, write out all the equations you have, and we'll see :smile:
 

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