Solving Missile Motion Problems: Answers & Explanations

  • Thread starter Thread starter malay ko
  • Start date Start date
  • Tags Tags
    Missile Motion
Click For Summary
SUMMARY

The discussion focuses on solving missile motion problems using kinematic equations. The missile is launched with an initial velocity of 85 m/s at a 30-degree angle. The time to reach the highest point is calculated using the formula tf = -2 Voy sin teta / g, resulting in approximately 8.66 seconds. The maximum height and total horizontal distance require further application of kinematic equations, specifically v = v_0 + a t, which were not fully explored in the discussion.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion concepts
  • Familiarity with trigonometric functions, specifically sine and tangent
  • Basic grasp of gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Learn how to derive maximum height using the formula h = Voy² / (2g)
  • Study the calculation of horizontal distance using the formula R = (Vox * tf)
  • Explore the application of the range equation for projectile motion
  • Investigate the effects of varying launch angles on projectile trajectories
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in mastering projectile motion calculations and kinematic equations.

malay ko
Messages
1
Reaction score
0

Homework Statement


A missile is fired with an initial velocity of 85 m/s at an angle of 30 degrees from the horizontal.

A) After how many seconds will the missile reach the highest point?
B) What is the maximum height reached by the missile?
C) Calculate the total horizontal distance traveled by the missile until it hits the ground.


Homework Equations



teta = arc tangent Voy/Vox

Vfx = Vocoy teta t

tf = -2 Voy sin teta / g

The Attempt at a Solution



A) tf = -2 Voy sin teta / g
= -2 (85m/s) (sin 30) / 9.81m/s^2
= -85m/s / 9.81m/s^2
= -8.66 s

B and C i don't know which formula to use
 
Physics news on Phys.org
malay ko said:
tf = -2 Voy sin teta / g

The Attempt at a Solution



A) tf = -2 Voy sin teta / g
= -2 (85m/s) (sin 30) / 9.81m/s^2
= -85m/s / 9.81m/s^2
= -8.66 s
Apply the following formula to the vertical motion:
v = v_0 + a t
B and C i don't know which formula to use
Some useful kinematic formulas are summarized here: https://www.physicsforums.com/showpost.php?p=905663&postcount=2"
 
Last edited by a moderator:

Similar threads

Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
33
Views
5K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K