Solving Nonhomogeneous Heat Equation with Fourier Transform

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SUMMARY

The discussion focuses on solving the nonhomogeneous heat equation using Fourier Transform techniques. The equation presented is \(\frac{\partial}{\partial t}\hat u_c(\omega,t) + (\omega^2 + 1)\hat u_c(\omega,t) = -f(t)\). An integrating factor, specifically \(e^{\int(\omega^2 + 1)dt}\), is suggested to simplify the equation. Participants are seeking clarity on how to apply this integrating factor effectively to arrive at a solution.

PREREQUISITES
  • Understanding of Fourier Transform techniques
  • Familiarity with differential equations
  • Knowledge of integrating factors in solving ODEs
  • Basic concepts of nonhomogeneous heat equations
NEXT STEPS
  • Study the application of integrating factors in ordinary differential equations
  • Research Fourier Transform methods for solving partial differential equations
  • Explore the implications of nonhomogeneous terms in heat equations
  • Learn about the properties and applications of the heat equation in physics
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Mathematicians, physicists, and engineering students who are working on differential equations, particularly those interested in heat transfer and Fourier analysis.

ColdFusion85
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How would one obtain a Fourier Transform solution of a non homogeneous heat equation? I've arrived at a form that has

[tex]\frac{\partial }{ \partial t }\hat u_c (\omega,t) + (\omega^2 + 1)\hat u_c (\omega,t) = -f(t)[/tex]

My professor gave us the hint to use an integrating factor, but I don't see how this would work. If [tex]p(x) = (\omega^2 + 1)[/tex], and [tex]q(x) = -f(t)[/tex], then the integrating factor would be [tex]e^{\int(\omega^2 +1)dw}[/tex]

Multiplying through by this would not give the usual integrating factor form of (..)' on the left hand side. Can anyone help?
 
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Anybody?
 
The integrating factor is :
[tex] e^{\int(\omega^2 +1)dt}[/tex]

but I don't know what to do next
 

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