Solving ODEs for Velocity & Limiting Velocity

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SUMMARY

The discussion focuses on solving ordinary differential equations (ODEs) related to the motion of a mass, m, dropped from rest under the influence of gravity and drag, represented by the equation of motion F = m(dv/dt) = -mg - mkv. Participants emphasize the need to express the equation in terms of ODEs, where g and k are constants. The calculation of velocity as a function of time and the determination of limiting velocity at large time intervals are also highlighted as key components of the problem.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Knowledge of Newton's second law of motion
  • Familiarity with concepts of drag force and terminal velocity
  • Basic calculus for solving differential equations
NEXT STEPS
  • Study the derivation of ODEs in physics, particularly in motion under gravity
  • Learn how to solve first-order linear differential equations
  • Explore the concept of terminal velocity and its mathematical implications
  • Practice problems involving forces and motion with drag
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This discussion is beneficial for physics students, educators, and anyone involved in mechanics or applied mathematics, particularly those focusing on motion analysis and differential equations.

keelejody
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i have a question but no mark scheme so i can't see where I am going wrong. a mass, m, is dropped with speed zero from point O at time t=0 after time t it has traveled x. the body is subject to acceleration due to gravity and drag -mkv.

(A) write the equation of motion:

ok so i know v=dx/dt

and I've said f=m(dv/dt)

so f=m(dv/dt)=-mg-mkv? because theyre opposite

I can't think what else to write, since this is 5 marks... unless i need sort this in terms of ODE's where g and k are constants?

(B) calculate velocity as a function of time, and the limiting velocity at very large time.

so i need v(t)? from v=dx/dt and this is where i use ODE's and work out V.

again i can't see where the marks come from this is worth 8.
 
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I think you are missing half of your equation here

"f=m(dv/dt)=-mg-mkv"

"-mg-mkv" is the f side of the equation, because those are the forces acting on it. You are missing the values for the m(dv/dt) side.

F = m(dv/dt)
-mg-mkv = ?

Also, you aren't supposed to post homework here, there is a special thread for that.
 


thanks I am still new to stuff and thanks :cool:
 

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