Solving Parametric Equations for a Torus: Normal & Surface Areas

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To solve the parametric equations for a torus, start by calculating the surface normal N(θ,Φ) using the cross product of tangent vectors derived from the derivatives of the parametric equations with respect to θ and Φ. The surface area can be determined by converting the integral formula into an integral over the variables θ and Φ, which may involve some manipulation. A visual representation can aid in understanding the geometry involved. For further study, seek out books or online resources that cover parametric surfaces and their properties in detail. Understanding these concepts will clarify the process of calculating the normal and surface area of the torus.
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Could someone please give me a clue how to solve these parametric equations or a starting position.

torus specified by these equations

x=(R+rcosΦ)cosθ
y=(R+rcosΦ)sinθ
z=rsinΦ

calculate the normal to the torus N(θ,Φ) and entire surface area

p.s anyone recommend a book or a webresource that discusses this in detail as I am very confused.
 
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The formula for surface area in your book is:

\int dx\; dy

where the integral is over the whole surface.

You need to convert this into an integral over theta and phi. This might require some work.

To get the surface normal, you might take the cross product between two vectors that are tangent to the surface. To get vectors tangent to the surface, take a look at the deriviative of x(theta,phi) where "x" stands for the three vector (x,y,z), with respect to theta and phi. Make a drawing and you may likely see what is going on.

Carl
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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