Solving Pressure in U-tube with Different Densities

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SUMMARY

The discussion focuses on the behavior of two liquids with different densities in a U-tube, specifically liquids A and B with densities of 1.0 g cm-3 and 0.8 g cm-3, respectively. Participants clarify that liquid A can indeed be positioned above liquid B due to its higher density, as the pressure at the same height must remain equal. The key equation used is P = ρgh, which relates pressure to density, gravitational acceleration, and height. The conversation emphasizes the counterintuitive nature of density arrangements in fluid mechanics.

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Homework Statement


Two liquids A and B of densities 1.0 g cm-3 and 0.8 g cm-3 are poured into an U-tube as shown in the figure below. Find x !

untitled.jpg


Homework Equations


P = \rho g h


The Attempt at a Solution


Is it possible liquid A is on top of liquid B because A has higher density than B?

Or do I misinterpret the question? Is it possible the question means density of A is 0.8 g cm-3 and B is 1.0 g cm-3 because there is no word "respectively" ?

Thanks
 
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songoku said:
Is it possible liquid A is on top of liquid B because A has higher density than B?
Sure, why not? Look at the diagram. Note that the height of liquid A is less than that of liquid B. There's a reason for that!
 
The statement looks correct, A is more dense than B. At the line PQ the pressure is the same. So more height of liquid above point P is needed to maintain the pressure the same as at point A.
 
Hi Doc Al and kuruman

Oh so it's possible that liquid with higher density is on top of liquid with lower density. I always think it's impossible.

I get it now. Thanks a lot Doc Al and kuruman ^^
 
songoku said:
Hi Doc Al and kuruman

Oh so it's possible that liquid with higher density is on top of liquid with lower density. I always think it's impossible.

I get it now. Thanks a lot Doc Al and kuruman ^^

Just imagine an iron piston pressing down on water in the U-tube and you'll see why it's possible.
 

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