Solving Q for an Unknown Gas - Warren's Homework

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SUMMARY

The discussion focuses on calculating the heat transfer (Q) for an unknown gas using the formula Q = (molar heat capacity) × (moles) × (temperature change). In this case, with 2.5 moles of gas, a molar heat capacity of 2.00 J/mol°C, and a temperature change (∆T) of 20.5°C, the calculated Q is 102.5 J. The constant pressure condition allows the use of molar heat capacity directly, confirming that the approach is valid without needing to convert to specific heat and grams.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically heat transfer.
  • Familiarity with the concept of molar heat capacity.
  • Basic knowledge of the ideal gas law and its applications.
  • Ability to perform unit conversions and dimensional analysis.
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  • Study the relationship between molar heat capacity and specific heat in thermodynamics.
  • Explore the implications of constant pressure conditions on gas behavior.
  • Learn about heat transfer calculations in different states of matter.
  • Investigate the ideal gas law and its applications in real-world scenarios.
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Students in chemistry or physics, educators teaching thermodynamics, and anyone involved in heat transfer calculations for gases.

Whalstib
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Homework Statement


Unknown gas:
Solving for Q
2.5 moles
Molar heat capacity 2.00J/mol°C
∆T=20.5
P constant .995

My question is I'm used to seeing this eqn. with specific heat and grams. Since given molar heat capacity and moles does it still work?
Constant P allows me to ignore it in this type of eqn?

Homework Equations


The Attempt at a Solution



Q=(2.00J/mol°C)(2.50 mol)(20.5 °C) = 102.5 J

Thanks,

Warren
 
Last edited:
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Your units match up, and it looks good to me.
 

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