Solving Q for an Unknown Gas - Warren's Homework

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Homework Statement


Unknown gas:
Solving for Q
2.5 moles
Molar heat capacity 2.00J/mol°C
∆T=20.5
P constant .995

My question is I'm used to seeing this eqn. with specific heat and grams. Since given molar heat capacity and moles does it still work?
Constant P allows me to ignore it in this type of eqn?

Homework Equations


The Attempt at a Solution



Q=(2.00J/mol°C)(2.50 mol)(20.5 °C) = 102.5 J

Thanks,

Warren
 
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