- #1

- 9

- 0

I1(0-j5) + I1(5+j5) - I3(5+j5) - 20 = 0

I2(5+j5) + I2(0-j10) + I3(0-j10) - 20 = 0

I1(0-j5) + I3(10+j0) - I2(5+j5) = 0

Does anyone have the link to any online software I could use to solve the problem? I have tried solving it by hand but seem to get a bit stuck. Can the I1(0-j5) + I1(5+j5) terms be combined to form 2I1(5) = 10I2 ? Likewise I2(5+j5) + I2(0-j10) = 2I2(5-j5) is this possible?