1. The problem statement, all variables and given/known data Image Attached 2. Relevant equations Impedance/Reactance Mesh Analysis 3. The attempt at a solution KVL -V + 2I1 + 4.7(I1 - I2) + j2(I1 - I3) = 0 4.7(I2 - I1) - j0.056(I2) + 2(I2 - I3) = 0 j2(I3 - I1) + 2(I3 - I2) + I3 = 0 (4.7 + j2)I1 - 4.7I2 - j2(I3) = 4V 4.7(I2-I1) - j0.056(I2) + 2(I2 - I3) = 0 -j2(I1) - 2I2 + (3 - j2)I3 = 0 Solve the second and third equation for I2 and I3, respectively. I2 = (4.7I1 + 2I3)/(6.7 - j0.056) I3 = (2(I2) + j2(I1)) / (3 - j2) Substitute I3 into I2, in order to eliminate one of the variables. (4.7I1 + 2(2I2 + j2(I1)/(3 - j2)) / (6.7 - j0.056) This is where things get a little confusing for me, and I'm not sure how to proceed. I was going to multiply by the conjugate in order to simplify the equation, but am I able to do this with 2 variables (I1 and I2)?? I did it for the equation I3. Also, is it possible to calculate this within Matlab? I know how to reduce linear equation (rref), but not sure how to account for the imaginary values (j) and the multiple currents (I1, I2, and I3). Any tips please? Hope it is easy to follow. Thanks so much!