Solving Refractive Indexes Homework: Wavelength & Index of Refraction

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The discussion revolves around solving a homework problem involving the refractive index of glass and the wavelength of light in glass. The problem uses Snell's Law, which relates the angles of incidence and refraction to the indices of refraction of the two media. The initial attempt at a solution incorrectly interpreted the wavelength as the refractive index, leading to confusion. Clarifications were provided regarding the definition of the refractive index and the correct application of Snell's Law. The conversation concludes with encouragement to evaluate the equations correctly for finding the refractive index and wavelength in glass.
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Homework Statement


A beam of light from a laser in a vacuum has a wavelength of 632.8nm and is incident on the surface of a glass slab. In the vacuum the beam make an angle of 32degrees witht the normal to the surface, while in the glass is makes an angle of 21.0degrees with the normal.

a)what is the index of refraction of the glass?

b)what is the wavelength of light in the glass?


Homework Equations


snell's law

wavelength1/wavelength2=n1/n2



The Attempt at a Solution



i know the wavelength is 632.8 so i tried subbing them into snells law and got
632.8sin32=n2sin21
but the answer i got couldn't be right, its 243 and this could be the refractive index.

hellppp!
 
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Check what is Snell's law exactly.

ehild
 
snell's law= n1sinangle1=n2singangle2
 
It is OK, but 632.8 nm is wavelength, not refractive index. What is the refractive index of vacuum?

ehild
 
the only other information i have is the speed of light in vacuum which is 3x10^8
 
And how is the refractive index defined?

ehild
 
when vi=c do you make it
sinangle=nsinangle and solve for n?
 
yes.ehild
 
thanks for your help!
 
  • #10
sin32=nsin21 just writing it here so i remember when i come back
 
  • #11
anotherperson said:
sin32=nsin21 just writing it here so i remember when i come back

Yes, evaluate.

ehild
 
  • #12
yep, thanks!
 

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