Solving Series w/ Remainder Estimate & Integral Test

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skyturnred
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It asks "use remainder estimate for integral test" to find series accurate to 3 dec?

Homework Statement



It says "Use the Remainder Estimate for the Integral Test to find the sum of the following series to three decimal places of accuracy."

[itex]\sum^{\infty}_{n=1}[/itex] [itex]\frac{1}{n^{3}}[/itex]

Homework Equations





The Attempt at a Solution



OK, so my question is as follows. If it says "to 3 decimal places of accuracy," what am I finding exactly? Am I finding the sum for error<0.001? or is it error<0.0005? I ask this because an error of 0.0005 could change the round and change the third decimal place.

As for the rest of the question, I know how to do it.

Thanks!
 
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skyturnred said:

Homework Statement



It says "Use the Remainder Estimate for the Integral Test to find the sum of the following series to three decimal places of accuracy."

[itex]\sum^{\infty}_{n=1}[/itex] [itex]\frac{1}{n^{3}}[/itex]

Homework Equations





The Attempt at a Solution



OK, so my question is as follows. If it says "to 3 decimal places of accuracy," what am I finding exactly? Am I finding the sum for error<0.001? or is it error<0.0005? I ask this because an error of 0.0005 could change the round and change the third decimal place.

As for the rest of the question, I know how to do it.

Thanks!

i have always used < 0.0005, just because of the possibility of "rounding error" changing the 3rd decimal place.
 


Thanks! Thats what Ill do!