Solving Silver + Nitric Acid Equation

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SUMMARY

The correct chemical equation for the reaction between silver (Ag) and nitric acid (HNO3) is 3Ag + 4HNO3 -> 3AgNO3 + 2H2O + NO2. In this reaction, silver is oxidized by the nitrate ion (NO3-) rather than by hydrogen ions (H+). The products include silver nitrate (AgNO3), water (H2O), and nitrogen dioxide (NO2). Understanding the oxidation states and the role of nitric acid as an oxidizing agent is crucial for accurately representing this reaction.

PREREQUISITES
  • Basic knowledge of oxidation-reduction reactions
  • Understanding of chemical equations and stoichiometry
  • Familiarity with the properties of nitric acid as an oxidizing agent
  • Knowledge of the oxidation states of silver and nitrogen compounds
NEXT STEPS
  • Study the oxidation-reduction reactions involving transition metals
  • Learn about the properties and reactions of nitric acid
  • Explore the formation and characteristics of nitrogen oxides
  • Investigate the stoichiometry of complex chemical reactions
USEFUL FOR

Chemistry students, educators, and professionals seeking to deepen their understanding of redox reactions and the behavior of silver in acidic environments.

Aditya2006
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A silver wire is added to nitric acid.

I got 2Ag + 2HNO3 -> H2 + 2AgNO3. It's not right though, can anyone help me?
 
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Ag is not oxidized by H+ but by NO3-. Try with NO2 between products.
 

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