Solving Stearic Acid Problems - Questions & Answers

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The discussion focuses on calculating the mass and volume of stearic acid in a solution. For a 0.01 mL solution containing 2 grams per liter of stearic acid, the calculated mass is 2 x 10^-5 grams. When considering the density of stearic acid at 0.9408 g/mL, the volume left after evaporating acetone is calculated to be 2 x 10^-8 liters. The initial poster expresses uncertainty about the accuracy of these calculations. Responses confirm that the calculations appear correct.
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Hi,

I have two questions that I am stuck on involving stearic acid solutions.


1a) 0.01mL of a solution containing 2 grams per litre of stearic acid in acetone is used. What mass of stearic acid is present in this drop of solution?


Solution:

0.01ML solution X (1L/1000mL solution) X 2g stearic acid/1L solution
= 2 x 10^-5 g


1b)The density of stearic acid is 0.9408g/mL. What will be the volume of stearic acid left from the drop of solution when all the acetone is evaporated?

Solution:

.00002g stearic acid X (1mL/0.9408g stearic acid) X (1L/1000mL)
= 2 x 10^-8 L

These are the best solutions I could come up with but I have a feeling both are incorrect. Any help would be appreciated.

thank you.
 
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max1205 said:
Hi,

I have two questions that I am stuck on involving stearic acid solutions.


1a) 0.01mL of a solution containing 2 grams per litre of stearic acid in acetone is used. What mass of stearic acid is present in this drop of solution?


Solution:

0.01ML solution X (1L/1000mL solution) X 2g stearic acid/1L solution
= 2 x 10^-5 g


1b)The density of stearic acid is 0.9408g/mL. What will be the volume of stearic acid left from the drop of solution when all the acetone is evaporated?

Solution:

.00002g stearic acid X (1mL/0.9408g stearic acid) X (1L/1000mL)
= 2 x 10^-8 L

These are the best solutions I could come up with but I have a feeling both are incorrect. Any help would be appreciated.

thank you.
Both look fine.
 
Thank You!
 
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