Solving Steering Equations for Vehicle Control

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SUMMARY

The discussion focuses on solving steering equations for vehicle control, specifically addressing the relationship between steering angle, radius of curvature, and vehicle velocity. The key equations include phi = T * st (where T is a constant), R = L/tan(phi), and str. = 30 * (V/R), which relates the steering rate to the vehicle's forward velocity and curvature. The user seeks clarification on the meaning of the constant T and the application of the str. equation in determining vehicle dynamics.

PREREQUISITES
  • Understanding of control systems and vehicle dynamics
  • Familiarity with trigonometric functions and their applications in steering
  • Knowledge of basic physics principles related to motion and curvature
  • Experience with programming concepts for implementing control algorithms
NEXT STEPS
  • Research the role of time constants in control systems
  • Learn about the dynamics of vehicle steering and the significance of the radius of curvature
  • Explore the implementation of steering equations in simulation software like MATLAB or Simulink
  • Study the effects of vehicle velocity on steering response and control strategies
USEFUL FOR

Automotive engineers, control system designers, and students in vehicle dynamics who are looking to deepen their understanding of steering control equations and their practical applications in vehicle navigation.

johngeo
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Hi,
I am new to control system and coding.my problem is suppose we have a steering value and know we need to turn the vehile. I facing difficulty in understanding some equations.

Code:
       phi=T*st. %here st. is steering value and 'T' is some constant , 
but I am facing difficulty to understand what it is? whether it is time constant or something else.
           % radius of curvature (ICC)
            R=L/tan(phi);
            str.=30*(V/R);% cann't understand what the use of this equation. here 'v' is some constant.
            theta new=theta+str.; %theta is vehicle angle.
            %centre of curvature(ICC)
            A=X-R*sin(theta);
            B=Y+R*cos(theta);
            %new position of rear axle mid point
            X=A+R*sin(theta new);
            Y=B-R*cos(theta new);
 
Last edited:
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Code:
str.=30*(V/R);% cann't understand what the use of this equation. here 'v' is forward velocity of vehicle.
image_from_jhki.png

please help me in understanding the concept of this equation.
How can we get an angle from R (ICC) and V (velocity)
 
Last edited:

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