Solving Stress-Strain Curve: Ultimate Stress, Units Confirmation

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SUMMARY

The discussion centers on determining the ultimate stress for a stress-strain curve of a soft aluminum alloy. The key equations involved include E=σ/ε, σ=P/A, and ε=δ/L0. The ultimate strength is defined as the stress at fracture, and the participant seeks confirmation on the correctness of their unit setup. The consensus is that the units appear to be set up correctly, and the ultimate strength is indeed the maximum stress before fracture occurs.

PREREQUISITES
  • Understanding of stress-strain relationships in materials science
  • Familiarity with the concepts of modulus of elasticity and yield strength
  • Knowledge of unit conversions in mechanical engineering
  • Experience with graphing stress-strain curves
NEXT STEPS
  • Review the calculation of ultimate strength in soft aluminum alloys
  • Study the significance of the modulus of elasticity in material properties
  • Learn about different types of stress-strain curves for various materials
  • Explore unit conversion techniques in engineering applications
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Materials scientists, mechanical engineers, and students studying material properties and stress analysis will benefit from this discussion.

aaronfue
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Homework Statement



I was creating a stress-strain curve for a soft aluminum alloy (as stated in problem) and was looking to find the ultimate stress and ensure my units were all okay.

I have attached a screenshot of my graph. And a separate screenshot with the formulas.

Homework Equations



E=σ/ε
σ=P/A
ε=δ/L0

The Attempt at a Solution


I think I have my graphs correct. I am aware of how to get the modulus of elasticity, yield strength, but the ultimate strength is confusing me on this one. It couldn't be the strength at fracture. How can I find it?

Also, if anyone could confirm that my units are set up correctly, I would greatly appreciate it.
 

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Ultimate strength means the stress at fracture. Once the sample fractures, it cannot support any more stress.

Your units look OK.
 
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