Solving SUVAT: Finding T from 2.5m/s to 7.5m/s over 45m

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Homework Help Overview

The problem involves a mass accelerating from an initial velocity of 2.5 m/s to a final velocity of 7.5 m/s over a distance of 45 meters. The original poster seeks to find the acceleration and the time taken for this change in velocity, specifically focusing on how to rearrange the equation for time.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the equation s = 0.5(u + v)t but expresses difficulty in rearranging it to isolate t. Some participants discuss the concept of average speed and suggest methods for manipulating the equation.

Discussion Status

Participants are engaging in a dialogue about algebraic manipulation and its importance in solving physics problems. Some guidance has been offered regarding the rearrangement of the equation, and the original poster expresses appreciation for the clarification received.

Contextual Notes

The original poster mentions feeling "useless" at rearranging equations, indicating a potential barrier to understanding. There is also a reference to seeking additional tutoring, suggesting a desire for further support in the subject.

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Homework Statement


A mass accelerates from 2.5ms^(-1) to 7.5ms^(-1) over a distance of 45m. Find the acceleration and the time it takes to do this.


Homework Equations


I know I need to use s=0.5(u+v)t

But I have no idea how to rearrange it to find t, I am useless at rearranging equations.


The Attempt at a Solution


I got t=0.5(u+v)-s

I know I did it wrong because I have the answer to the questions here, But It's not really what I'm looking for.

I need to know how to do it.

Any help would be appreciated.

Cheers,
Ben
 
Last edited:
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if I gave you the equation [itex]y=Ax[/itex]...could you solve it for [itex]x[/itex]?
 
The "0.5(u+v)" part of the equation is the "average speed." Quite literally it is one half of the sum of initial and final velocities. If it is written as (u+v)/2 it makes more sense.

But I am guessing (based on the way you wrote the unit for velocity) that your textbook, or teacher, likes to put everything "above the line."

Anyway, to solve for t, multiply both sides of the equation by 2, then divide both sides by (u+v).

Warning: you better get better than "useless" at algebraic manipulation really quickly, otherwise Physics will get impossible for you. This is one of the main features of problem solving. Get tutorial help ASAP
 
Chi Meson said:
The "0.5(u+v)" part of the equation is the "average speed." Quite literally it is one half of the sum of initial and final velocities. If it is written as (u+v)/2 it makes more sense.

Something in your explanation made everything click into place. I guess the late nights aren't helping at the moment. Thanks very much and I'm looking into getting extra tuition.

Thanks once again,
Ben
 

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