Solving Sys of Difeq: Matrix, Eigen Values, Det, Calculus, Algebra

  • Thread starter Thread starter marmot
  • Start date Start date
  • Tags Tags
    Systems
Click For Summary
SUMMARY

The discussion focuses on solving a system of differential equations using matrix manipulation, eigenvalues, and calculus. The user initially attempted to find eigenvalues through determinants but encountered issues leading to zero values. They then shifted to solving the system directly with calculus, successfully deriving x1 as 8exp(-20t). However, they faced difficulties with x2, which was incorrectly calculated due to a missing multiplication factor. The clarification provided indicates that an eigenvalue of zero is valid and represents a constant solution.

PREREQUISITES
  • Understanding of differential equations and their solutions
  • Familiarity with matrix manipulation and eigenvalues
  • Knowledge of calculus, specifically integration techniques
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study eigenvalue problems in linear algebra
  • Learn advanced techniques for solving systems of differential equations
  • Explore matrix exponentiation and its applications in differential equations
  • Review integration methods in calculus for solving differential equations
USEFUL FOR

Students and educators in mathematics, particularly those focusing on differential equations, linear algebra, and calculus. This discussion is beneficial for anyone seeking to deepen their understanding of solving systems of differential equations using various mathematical techniques.

marmot
Messages
55
Reaction score
1

Homework Statement


http://img412.imageshack.us/img412/6463/difeq.jpg


Homework Equations



Matrix maniupation, egein values, determinant, etc

The Attempt at a Solution



Well, at first I tried the formulaic way, i.e. finding the eigenvalue through the determinant, but it gave me zero and worse when plugged in it gives zero for x1 and x2.

It seems it is too simple to use matrixes here so Instead I just tried it the old fashioned way - i.e. solving for the system through calculus and algebra.

So

x1'=-20x1
x2'=-10x1

So I solved for x1 because it seemed pretty straightforward and it was, I got:

x1=8exp(-20t)

which is correct

So now I try plugging it in x2' and integrating dx2/dt and I get

x2-8=2exp(-20t)/5-2/5

which should give

x2=2exp(-20t)/5-2/5+8

However this is wrong. can someone help me with this?
 
Last edited by a moderator:
Physics news on Phys.org
When you plugged in x1, you forgot to multiply by -10 and your integration came out incorrectly.

Also, an eigenvalue of 0 is perfectly acceptable. It's simply a constant solution.
 
Last edited:

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
11
Views
6K
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 2 ·
Replies
2
Views
7K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K