Solving Tension in Hanging Sign: 117 N or Wrong?

[iluvcanucksfo]

A purple beam is hinged to a wall to hold up a blue sign. The beam has a mass of mb = 6.2 kg and the sign has a mass of ms = 15.1 kg. The length of the beam is L = 2.78 m. The sign is attached at the very end of the beam, but the horizontal wire holding up the beam is attached 2/3 of the way to the end of the beam. The angle the wire makes with the beam is θ = 30.6°.

What is the tension in the wire?

I have set the torques of the beam's weight and the sign's weight equal to the tension torque as follows:
(6.2)(9.8)(.5)(2.78)(cos30.6) + (15.1)(9.8)(2.78)(cos30.6) = (T/sin30.6)(2/3)(2.78)

Solving for T, I keep getting 117 N which is not the right answer...
Could anyone explain where I am going wrong?

 

[grzz]

(6.2)(9.8)(.5)(2.78)(cos30.6) + (15.1)(9.8)(2.78)(cos30.6) = (T/sin30.6)(2/3)(2.78)
Could anyone explain where I am going wrong?

Replace '/' by 'times'