Solving the Charged Bubble Problem with Gas and Electrostatic Forces

  • Thread starter Thread starter Ahmed Farhan
  • Start date Start date
  • Tags Tags
    Bubble Charged
Ahmed Farhan
1.
3016.jpg
2. The force due to gas pressure = p(V0/V) dA
The force due to atmospheric pressure = p dA
The force due to electrostatic repulsion = undetermined

3. Though I don't surely know what the expression for electric force should be, I took an educated guess and solved using the relation:
force of gas pressure + electric repulsion = atmospheric pressure force
but couldn't get the expression asked for in the problem. Can anyone please take a look?
 
Physics news on Phys.org
Please show details of your attempt. The question refers to problem 15. Is there anything in that problem that you could list as relevant to this problem?
 
electrostatic pressure = σ2/2ε0
where σ=q/(4πR2)
now,
pV0/V + σ2/2ε = p
V0=4/3*π*R03 and V=4/3*π*R3
this follows the result
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top