1. The problem statement, all variables and given/known data A gas initially occupying a volume V undergoes a sudden explosion, causing its volume to triple to 3V. Assuming that the pressure of the environment (atmospheric pressure po) remains constant, find an expression for the work done by the gas. Hint: Please notice that an explosion is a rapid and irreversible process. Because this process happens far from equilibrium, the pressure of the gas (p) is not well defined and the expression dw = - pdV cannot be applied to the gas undergoing the explosion. 2. Relevant equations pv=nRT dU = TdS-pdV dU = dQ+ dW 3. The attempt at a solution I'm not really sure how to even begin. I was trying to relate this to the Joule free expansion, but I don't think that is correct. I think entropy will come into account.