Solving the Friction Dilemma Homework Statement

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SUMMARY

The discussion focuses on solving a physics problem involving the maximum volume of sand that can be piled in a cone shape on a circular area without spilling. The formula derived is V = (π * [u] * R³) / 3, where [u] represents the static coefficient of friction and R is the radius of the circular area. Participants clarify the relationship between the height of the cone (h) and the coefficient of friction, concluding that h can be expressed as [u]R. The tangent of the angle between the radius (R) and the slant height (L) is also discussed, establishing that tan(φ) = [u], which is crucial for understanding the problem.

PREREQUISITES
  • Understanding of cone volume formula: V = Ah/3
  • Knowledge of static friction and its coefficient
  • Familiarity with trigonometric functions, specifically tangent
  • Basic principles of inclined planes in physics
NEXT STEPS
  • Study the derivation of the volume of a cone and its geometric properties
  • Learn about static friction and its applications in physics problems
  • Explore trigonometric identities and their relevance in physics
  • Investigate inclined plane mechanics and frictional forces
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Students studying physics, particularly those focusing on mechanics and friction, as well as educators looking for examples of practical applications of geometric and trigonometric concepts.

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Homework Statement


Q: A worker wishes to pile a cone of sand onto a circular area in his yard. The radious of the circle is R, and no sand is to spill into the surrounding area. If is the static coefficient of friction between each layer of sand along the slope and the sand beneath it (along which it might slip), show that the greatest volume of sand that can be stored in this manner is
(pi**R3)/3.
(The volme of a cone is Ah/3, where A is the base area and h is the cone's height).


sorry, should've stated:
I've sat here thinking about this question for about 3 hrs now to no avail.

the only thing I can scratch up is the fact that since V =Ah/3 and V(cone)= (pi**R3)/3.
that means h = R.

But I don't know how that works...
 
Last edited:
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Hi! You´ve written V =(pi**R3)/3. Does your R3 correspond to my R^3 (three-times R) ?
Then everything is o.k.
You´ve already written V =Ah/3 and so V = (pi*R^2*h)/3.
What you need to know now: How can I express “h” by ?
Look at the rectangular triangle formed by R and L (it’s the “half” of the cone).

I
III
IIIII
IIIIII L
IIIIIII
IIIIIIII
IIIIIIIII
IIIIIIIIII
R



Two things: 1)What is the tangent of the angle between R and L? Call it phi.
2)Remember that tan phi = ? This is the largest angle at which sth. can lie on the plane without slipping (you can derive this relation from the “inclined plane with friction” if you want to…)
Now substitute…

Greetings from Germany...
 
TYVM!
Made so much sense =).
TYVM.
 

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