Solving the Parallel Circuit: R=25, X[c]=100, X[L]=25

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
huma
Messages
7
Reaction score
0

Homework Statement


what is the value combined impedance of the parallel circuit ?when R=25 ,X[c]=100 and X[L]=25

Homework Equations


I think we use this equation to solve parallel impedance ...
acp176.gif
.

The Attempt at a Solution


z=1/√((squ(1/25))+(squ((1/25)-(1/100))))=1/√(1/625)+squ(3/100)=√10000/25=100/5=20
but the ans is given is 120 what I do ?
 
Physics news on Phys.org
Hi,
with your value(R=25,XL=25,XC=100) and your equation you found the right answer. Maybe you forget to convert L and C value to phasor form, it means ( XL=JwL not XL= L) or the book answer is wrong
 
no its is given the value of Xc and XL ... no need to find Xc and XL
vetre
 
huma said:
but the ans is given is 120
Perhaps it is a typo. The answer is j20, not 120.
The equivalent impedance of a bunch of parallel impedances is less than the least of them, which means the answer is less than 25.