Solving the Parallel Circuit: R=25, X[c]=100, X[L]=25

In summary, the conversation is about finding the combined impedance of a parallel circuit with given values for R, X[c], and X[L]. The attempted solution involves using an equation and converting the values to phasor form. However, the given answer of 120 is incorrect and the correct answer is j20. This is because the equivalent impedance of parallel impedances is always less than the least of them.
  • #1
huma
7
0

Homework Statement


what is the value combined impedance of the parallel circuit ?when R=25 ,X[c]=100 and X[L]=25

Homework Equations


I think we use this equation to solve parallel impedance ...
acp176.gif
.

The Attempt at a Solution


z=1/√((squ(1/25))+(squ((1/25)-(1/100))))=1/√(1/625)+squ(3/100)=√10000/25=100/5=20
but the ans is given is 120 what I do ?
 
Physics news on Phys.org
  • #2
Hi,
with your value(R=25,XL=25,XC=100) and your equation you found the right answer. Maybe you forget to convert L and C value to phasor form, it means ( XL=JwL not XL= L) or the book answer is wrong
 
  • #3
no its is given the value of Xc and XL ... no need to find Xc and XL
vetre
 
  • #4
huma said:
but the ans is given is 120
Perhaps it is a typo. The answer is j20, not 120.
The equivalent impedance of a bunch of parallel impedances is less than the least of them, which means the answer is less than 25.
 

Similar threads

Replies
2
Views
2K
Replies
7
Views
5K
Replies
5
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
Replies
4
Views
2K
Replies
5
Views
2K
Back
Top