Solving the Pigeonhole Principle Homework Problem

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SUMMARY

The discussion centers on a homework problem related to the Pigeonhole Principle, specifically demonstrating that within a set of 10 objects painted in 3 colors, there exist two disjoint subsets, each containing 3 objects of the same color. The initial confusion arose from the interpretation of the problem, particularly regarding the distinctness of colors. Ultimately, the solution confirms that it is indeed possible to form such subsets, as demonstrated by examples provided in the discussion.

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Homework Statement


The following is the question verbatim:

Imagine a set of 10 objects, each of which is painted one of 3 possible colors. Show that there exists 2 disjoint subsets of this set such that each subset consists of 3 objects all painted the same color.

The Attempt at a Solution



This is a problem that is supposed to demonstrate the pigeonhole principle. I know how to use said pigeonhole principle, so maybe it's just the wording that is confusing me.

Trivially, if I am allowed to choose among all possible sets of ten objects consisting of 3 colors (say r,g,b) then of course I can construct two disjoint sets each of which contain at least three objects of the same color. If the set is {r1 r2 r3 g4 g5 g6 g7 g8 g9 g10} then obviously {r1 r2 r3}, {g4, ..., g10} works. Of course there are many others.

On the same hand we're not guaranteed that in any decomposition of the set there are two disjoint sets containing at least three. For example {r1 r2 g3 g4 b5 b6 b7 b8 b9 b10} could be decomposed as say {r1 r2 g3 g4} {b5, ... b10}.

Maybe I'm misunderstanding the question? Could someone clear this up for me?
 
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Nevermind, I figured it out. For some reason I thought the colours had to be distinct also.
 

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