Solving the Problem of a Bus Running Out of Fuel on a Hill

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SUMMARY

The discussion centers on calculating the minimum speed required for a bus to coast to the top of a 3.54 m hill after running out of fuel. The relevant physics equation used is the conservation of energy formula, specifically 1/2mv^2 = mgh, where 'm' represents mass, 'v' is velocity, 'g' is the acceleration due to gravity, and 'h' is the height of the hill. The lack of specific mass or force information is noted, but the equation provides a clear method to derive the necessary speed.

PREREQUISITES
  • Understanding of basic physics concepts, particularly energy conservation.
  • Familiarity with the equation for gravitational potential energy (mgh).
  • Knowledge of kinetic energy (1/2mv^2).
  • Basic algebra skills for solving equations.
NEXT STEPS
  • Calculate the minimum speed using the equation 1/2mv^2 = mgh with g = 9.81 m/s².
  • Explore the implications of mass on the speed calculation in energy conservation problems.
  • Investigate real-world applications of energy conservation in vehicle dynamics.
  • Review similar physics problems involving potential and kinetic energy conversions.
USEFUL FOR

Students studying physics, educators teaching energy conservation principles, and anyone interested in solving practical problems involving motion and energy.

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Homework Statement


A bus runs out of fuel as it approaches a hill. If the hill is 3.54 m high, how fast must the bus be traveling in order to coast just to the top of the hill?


Homework Equations





The Attempt at a Solution


How do we solve this problem?? We aren't given any
information (mass, forces or anything)?
 
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1/2mv^2 = mgh
 
thank you much
 

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