Solving the Rocket Ship Problem

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Homework Help Overview

The problem involves two rocket ships with a rest length of 100 meters each, analyzed within the context of special relativity. The scenario describes their positions in two different reference frames, S and S', and involves concepts such as length contraction and Lorentz transformations to determine the relative speed of the frames.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the relative velocity of the two rocket ships using length contraction and time measurements from frame S. They express uncertainty about their approach and seek validation. Other participants confirm the original poster's calculations and express their own thoughts on subsequent parts of the problem.

Discussion Status

The discussion is active, with participants engaging in the exploration of the problem. Some guidance has been provided regarding the calculations, and there is a shared acknowledgment of the complexity of the concepts involved. Multiple interpretations of the problem's requirements are being explored, particularly regarding the second part of the question.

Contextual Notes

Participants are navigating the intricacies of relativity, with some expressing feelings of confusion. There is an emphasis on ensuring understanding rather than simply arriving at answers.

strangequark
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Homework Statement



Two rocket ships, each with a rest length of 100 meters. Rocket 1 is at rest in frame S and has nose at x=0, tail at x = +100 meters. Rocket 2 is at rest in frame S' and has nose at x' = 0 and tail at x'=-100 meters. Suppose S' moves with speed V in the positive x direction realtive to S. Event A synchronizes the two frames (x=x'=t=t'=0), and event B is when the tail o rocket 2 passes the nose of rocket 1 at time t=2.5 microseconds in frame S. Find the speed V...

Homework Equations



Length contraction, and the lorentz transforms.


The Attempt at a Solution



What I did was say that the distance rocket 2 moved as observed from the S frame was:

[tex]x_{b}=\frac{L_{0}}{\gamma}[/tex]

Then the velocity would be distance over time, or:

[tex]v=\frac{\frac{L_{0}}{\gamma}}{t_{B}}[/tex]

Then I solve for v and get something like .133c for my relative velocity...
Am I on the right track here?
 
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EDIT: Yes, you're right.
 
Last edited:
Awesome, thanks!... while you're here, the second part of the problem states that event C is the event that the nose of rocket 2 passes the tail of rocket 1 and asks for the time coordinate with respect to the S frame...

I'm thinking that I can just take the length of the ship (100 m) and divide by the relative velocity... but it seems too simple...
 
strangequark said:
Awesome, thanks!... while you're here, the second part of the problem states that event C is the event that the nose of rocket 2 passes the tail of rocket 1 and asks for the time coordinate with respect to the S frame...

I'm thinking that I can just take the length of the ship (100 m) and divide by the relative velocity... but it seems too simple...

Yes, that will give you the answer. BTW I get 0.132c for part 1.
 
Last edited:
Sorry, yeah, I end up with .132254c also.

Great... maybe I'm not as confused about this as I feel sometimes. I tend to think myself into circles with relativity...

I really appreciate you taking the time to look at this with me... Thanks!
 

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