Solving the Spring-Weight Paradox: 0.039m

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The discussion focuses on solving the spring-weight paradox by analyzing the forces acting on a spring when a weight is applied. The initial calculation shows that at maximum stretch, the spring force equals the weight, leading to a stretch of 0.01962 m. However, the solution key indicates the maximum stretch should be 0.039 m, prompting a reevaluation of the approach. The conversation suggests using the conservation of energy principle to address the discrepancy, particularly considering the effects of sudden changes in weight. This indicates a need to account for dynamic conditions rather than static equilibrium in the analysis.
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Homework Statement


upload_2014-11-23_7-54-12.png


Homework Equations



Fs = -kx

w = mg

The Attempt at a Solution



I said that when the spring is stretched out at its max, the weight pulling down will equal the force of the spring pulling up.

Fs=w
-kx = mg
-(1500)(x) = (3)(-9.81)

x = 0.01962 m

The solution key tells me the max stretch is double this amount, 0.039 m. What is wrong with my approach?
 
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Mark the word suddenly. If the basket were at maximum distance and forces would be in equilibrium, the velocity wouldn't change anymore, so the thing would hang still.
Do you think that is what would happen if you suddenly put a brick in the basket ?
 
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Ah. I see. So then I need to solve the problem using the conservation of energy.
 
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