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Solving trigonometric equation

  1. Apr 15, 2010 #1
    This is part of the identity proving question .

    from [tex]\sin C=\frac{2}{\sqrt{29}}[/tex] , how can i reach [tex]C=\frac{1}{2}\sin^{-1} (\frac{20}{29})[/tex] ?
  2. jcsd
  3. Apr 15, 2010 #2


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    Hi thereddevils! :smile:

    (have a square-root: √ and try using the X2 tag just above the Reply box :wink:)

    Hint: C = 1/2 sin-1 20/29 is the same as sin2C = 20/29 :wink:
  4. Apr 16, 2010 #3
    Re: trigonometry

    got it thanks !
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