Solving Turbine Force: Vo = +21 m/s, Vf = -21 m/s, 27.2 kg/s

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The discussion focuses on calculating the average force exerted on a turbine blade by a water stream with an initial velocity of Vo = +21 m/s and an exit velocity of Vf = -21 m/s, with a mass flow rate of 27.2 kg/s. The correct approach to determine the force involves applying the principle of momentum change, resulting in a force calculation of 2 * (21 m/s) * (27.2 kg/s) = 1145.44 N. Participants clarify that the force exerted on the blade is indeed equal and opposite to the force exerted by the blade on the water, in accordance with Newton's Third Law.

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A stream of water strikes a stationary turbine blade, as the drawing illustrates. The incident water stream has a velocity of vo=+21 m/s, while the exiting stream has a velocity of vf=-21 m/s. The mass of water per second that strikes the blade is 27.2 kg/s. Find the magnitude of the average force exerted on the water by the blade.

(There is a pic of a turbine forcing water to make a 90 degree angle).

Wouldn't it be correct to say that the force by the water on the blade is equal to the force on the blade by the water due to Newton's 3rd law?

so just take 21 * 27.2 = 571.2? Why is this wrong according to my book?
 
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wouldnt it be 2(21)(27.2) because final-initial = -21-21=-42...
 

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