Solving voltage divider involving capacitors

[wu_weidong]

Homework Statement

Given Z_V1 = Z_V2 = 100Ω,
Z_CCV = Z_CV = 2000/j = -2000j, and
V_V/V_C = 0.04789.

I'm trying to get the given V_V/V_C result.

Homework Equations

I know that
1/Z_V = 1/Z_V1 + 1/Z_V2 + 1/Z_CV
V_V = Z_V / (Z_V + Z_CCV) * V_C

The Attempt at a Solution

1/Z_V = 1/Z_V1 + 1/Z_V2 + 1/Z_CV = 1/100 + 1/100 + j/2000
|1/Z_V| = √(0.02² + (1/2000)²) = 0.02
Z_V = 50Ω

V_V/V_C = Z_V / (Z_V + Z_CCV) = 50 / (50 - 2000j)
V_C/V_V = (50 - 2000j) / 50 = 1 - 40j
|V_C/V_V| = √(1² + 40²) = 40.01
V_V/V_C = 1/40.01 = 0.02499
which is about half of the value I should get.

Where did I go wrong?

 

[Simon Bridge]

Kirkoffs laws - check arithmetic.

 

[wu_weidong]

Kirkoffs laws - check arithmetic.

Can I please have a bit more hint?

The voltage through Z_V1, Z_V2 and C_V is the same (V_V), right?