Solving Water Flow in a Taper Pipe Problem

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The problem involves calculating the speed of water in a tapered pipe using the continuity equation and Bernoulli's principle. The initial speed of water is 0.228 m/s with a pipe radius of 1.08 cm, and it tapers to a radius of 2.39 mm. The continuity equation indicates that the product of area and velocity must remain constant throughout the pipe. Users are encouraged to share their attempts and specific points of confusion for more targeted assistance. Understanding the principles of fluid dynamics is crucial for solving this problem effectively.
PhysicsCCR
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Homework Statement



Water entering a house flows with a speed of 0.228 m/s through a pipe of 1.08 cm inside radius. What is the speed of the water at a point where the pipe tapers to a radius of 2.39 mm?

Homework Equations


Continuity equation: A1V1 = A2V2

Bernoulli's Principle: P1 + .5pv1^2 + pgh1 = P2 + .5pv2^2 + pgh2, where P = Pressure,
p = density.

Volume of a cylinder = pi (r)^2 (h)

Area of a cylinder = 2pi (r)^2 + 2pi (r)h

The Attempt at a Solution

The problem seems simple enough, but I'm having trouble. Please help!
 
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Hi PhysicsCCR! :wink:

Water is incompressible.

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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