Can Water Flow in Multiple Directions in a Network of Pipes?

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Homework Help Overview

The discussion revolves around fluid dynamics in a network of pipes, specifically addressing the flow of water and the conditions under which it can occur in multiple directions. Participants reference previous discussions and notes regarding flow direction and pressure relationships in the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of equations governing fluid flow, questioning the setup and flow directionality. There are attempts to reconcile differing statements about flow direction and the relationships between flow rates (Q1, Q2, Q3).

Discussion Status

The discussion is active, with participants questioning the validity of previous assertions about unidirectional flow. Some suggest that the equations may allow for different interpretations, while others express skepticism about the feasibility of multiple flow directions.

Contextual Notes

There are references to constraints from previous threads and the need for clarity on the assumptions made regarding flow direction and pressure conditions in the pipe network.

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Homework Statement


in the previous therad
https://www.physicsforums.com/threads/flow-in-branch-pipe.866194/
(post #14) , i was told that water can flow in one direction only in a netwrok of pipes .
However , in the notes uploaded here , the author stated that when P is below surface of B , then water must be out of B and Q1 + Q2 = Q3 ?
I4r4Jk1.jpg

Homework Equations

The Attempt at a Solution


IMO , it should be Q2 = Q1 + Q3 , since i was told that water can only flow in 1 direction , am i right ? [/B]
 

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I would not have set this problem up the way that they have set it up. I would have written the following 3 equations:

$$\frac{p_A}{\rho g}+z_A=\frac{p_D}{\rho g}+z_D+\frac{fL_1v_1^2}{gd_1}$$
$$\frac{p_D}{\rho g}+z_D=\frac{p_B}{\rho g}+z_B+\frac{fL_1v_2^2}{gd_1}$$
$$\frac{p_D}{\rho g}+z_D=\frac{p_C}{\rho g}+z_C+\frac{fL_1v_3^2}{gd_1}$$
So,
$$z_A=\frac{p_D}{\rho g}+z_D+\frac{fL_1v_1^2}{gd_1}\tag{1}$$
$$\frac{p_D}{\rho g}+z_D=z_B+\frac{fL_1v_2^2}{gd_1}\tag{2}$$
$$\frac{p_D}{\rho g}+z_D=z_C+\frac{fL_1v_3^2}{gd_1}\tag{3}$$

What would Eqn. 2 have to look like if the flow were from B to D, rather than from D to B?
 
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Chestermiller said:
I would not have set this problem up the way that they have set it up. I would have written the following 3 equations:

$$\frac{p_A}{\rho g}+z_A=\frac{p_D}{\rho g}+z_D+\frac{fL_1v_1^2}{gd_1}$$
$$\frac{p_D}{\rho g}+z_D=\frac{p_B}{\rho g}+z_B+\frac{fL_1v_2^2}{gd_1}$$
$$\frac{p_D}{\rho g}+z_D=\frac{p_C}{\rho g}+z_C+\frac{fL_1v_3^2}{gd_1}$$
So,
$$z_A=\frac{p_D}{\rho g}+z_D+\frac{fL_1v_1^2}{gd_1}\tag{1}$$
$$\frac{p_D}{\rho g}+z_D=z_B+\frac{fL_1v_2^2}{gd_1}\tag{2}$$
$$\frac{p_D}{\rho g}+z_D=z_C+\frac{fL_1v_3^2}{gd_1}\tag{3}$$

What would Eqn. 2 have to look like if the flow were from B to D, rather than from D to B?
if the flow were from B to D ,
PB / ρg + zB = PD / ρg + zD +f(L_2)[(v_2)^2] / 2g(D_2) ,
as PB = 0 ,so ,
zB = PD / ρg + zD +f(L_2)[(v_2)^2] / 2g(D_2) , am i right ?
am i right ?
 
Last edited:
is the author wrong ? how could Q1 + Q2 = Q3 ? how could the water flow in different direction ?
in the previous thread , i was told that in order for water from Res. B to flow to the split at D, it must flow against the pressure in the line created by the flow from Res. A , so the water can only flow out from A , and into B and C..
https://www.physicsforums.com/threads/flow-in-branch-pipe.866194/
 
foo9008 said:
if the flow were from B to D ,
PB / ρg + zB = PD / ρg + zD +f(L_2)[(v_2)^2] / 2g(D_2) ,
as PB = 0 ,so ,
zB = PD / ρg + zD +f(L_2)[(v_2)^2] / 2g(D_2) , am i right ?
am i right ?
Yes. Now, see if there is a possible solution for this case.
 
Chestermiller said:
Yes. Now, see if there is a possible solution for this case.
what do you mean ?
 
foo9008 said:
what do you mean ?
This would be applicable to the case where Q1+Q2 = Q3. Do the equations have a solution for this case?
 
Chestermiller said:
This would be applicable to the case where Q1+Q2 = Q3. Do the equations have a solution for this case?
IMO , that is not feasible , since i was told that water can only flow in 1 direction
 
  • #10
foo9008 said:
IMO , that is not feasible , since i was told that water can only flow in 1 direction
If that's the case, then when you solve the equations, you will not get a real solution. Why don't you try solving it and see what you get. Who told you that silly thing anyway?
 
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  • #11
Chestermiller said:
If that's the case, then when you solve the equations, you will not get a real solution. Why don't you try solving it and see what you get. Who told you that silly thing anyway?
i was told in the previous thread , refer to the previous thread https://www.physicsforums.com/threads/flow-in-branch-pipe.866194/
 
  • #12
Chestermiller said:
If that's the case, then when you solve the equations, you will not get a real solution. Why don't you try solving it and see what you get. Who told you that silly thing anyway?
so , the statement of water can only flowing in 1 direction is incorrect ?
 
  • #13
anyone can clarify ?
 
  • #14
Chestermiller said:
This would be applicable to the case where Q1+Q2 = Q3. Do the equations have a solution for this case?
how to know that if the equations have solutions ?
 
  • #15
foo9008 said:
anyone can clarify ?
What direction would it be if D1 were equal to zero?
 
  • #16
foo9008 said:
how to know that if the equations have solutions ?
Solve them and see if the solution is real or complex.
 

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