SOme help with intergration by parts,

[maxpayne_lhp]

SOme help with intergration by parts, please

1. Find: \int e^x cos (x) dx

The Attempt at a Solution

I tried using integration by parts - what we are working on... all these 3 possibilities:

u = cos x, u= e^x, u = e^x cos(x)

And the \int vdu are, respectively:

1. \int e^x sin(x) dx <br /> <br /> &gt;&gt; 2.\int sin(x) e^x dx<br /> <br /> &gt;&gt; 3.\int x e^x cos(x) dx

which won't work out very well... Please give me a suggestion.

Thanks :)

PS: I don't know how to start a new line in the coded body :S srry

 

[rocomath]

Either will be fine. The concept behind this problem is that you have to do Parts more than once. After the 2nd or 3rd time, you will notice that you get your original Integral back, bring it to the other side and then just divide by the constant and you're pretty much done.

 

[unplebeian]

Use LAITE for future problems related to integration by parts.

L - Logarithmic function
A - Algebraic function
I - Inverse function (like arctan)
T - Trig function
E - Exponential function

So in your example, you have an exponential function and a trig function. According to the acronym, the trig function comes before Exponential function. So u= cos x.

This method had worked for ALL the integration by parts I have done so far
e.g. int(ln(x)) where you use 1 x ln(x). u= 1 in this case.

 

[quantumdude]

L - Logarithmic function
A - Algebraic function
I - Inverse function (like arctan)
T - Trig function
E - Exponential function

You've misspelled the acronym: It's LIATE. You'd have a real hard time integrating x\arctan(x) if you spelled it LAITE!

 

[unplebeian]

What he (Tom Mattson) said.

 

[HallsofIvy]

1. Find: \int e^x cos (x) dx

The Attempt at a Solution

I tried using integration by parts - what we are working on... all these 3 possibilities:

u = cos x, u= e^x, u = e^x cos(x)

And the \int vdu are, respectively:

1. \int e^x sin(x) dx <br /> <br /> &gt;&gt; 2.\int sin(x) e^x dx<br /> <br /> &gt;&gt; 3.\int x e^x cos(x) dx

If u= cos x, then du= -sin x dx and dv= exdx so v= e^x. Then
\int e^x cos x dx= -e^x cos x+ \int e^x sin x dx
Now, do it again, letting u= sin(x), dv= e^x dx. Your result will be
\int e^x cos(x)dx= something involving that same integral. combine them and solve for \int e^x cos(x)dx.

If u= e^x then du= e^xdx and dv= cos x dx so v= sin x. Then
\int e^x cos x dx= e^x sin x- \int e^x sin x dx
Again, repeat and do the same thing as in the first one

if u= e^x cos x then du= e^x cos x- e^x sin x and dv= dx so v= x. Your result will be
\int e^x cos x dx= x e^x cos x- \int xe^x cos x- xe^x sin x dx
which, I agree, doesn't seem to help. Use one of the first two methods.

which won't work out very well... Please give me a suggestion.

Thanks :)

PS: I don't know how to start a new line in the coded body :S srry