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Something about tangent vector

  1. Apr 12, 2010 #1
    hey there, i got stuck on an question here:
    Parameterise the following paths, in the dirction stated, and hence find a tagent vector(in the same dirction) to each point on the paths.
    (a)The upper part of the circled centred at (0,0) containing the points (-2,0) and (2,0) going anticlockwise.
    (b) the circle centred at (1,2,5) of radius three in the plane z=5 going clockwise (looking down the z axis)


    lol,really need help on these two questions. Thx everyone
     
  2. jcsd
  3. Apr 12, 2010 #2
    Can you tell us what you have attempted? In particular, do you have a clear understanding of what "tangent vector" means?
     
  4. Apr 12, 2010 #3
    honestly, i attempt another 3 similar questions but really have no idea on that one. all my understanding is that tangent vec. is the trace of a curve at given points...something like that hum? not sure if my understanding is correct...lol
     
  5. Apr 12, 2010 #4
    A tangent vector is essentially a vector that is tangent to the graph of your curve. Surely you know what "tangent" and "vector" mean. If you think of your curve as a position function (written in the form of a vector; see below), the tangent vector is equivalent to the velocity vector. The problem requires that you come up with a set of parametric equations x(t) and y(t) that would describe the position of a point on the specified curves. Then, using this position function, determine the tangent vector.

    If [itex]\vec{r}(t)[/itex] is the position vector, then

    [tex]\vec{r}(t) = x(t) \vec{\mathbf{i}} + y(t) \vec{\mathbf{j}}[/tex]
     
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