Space Curve Intersecting a Parabloid

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SUMMARY

The intersection of the space curve \(\vec{r}(t) = \langle t, 0, 2t - t^2 \rangle\) with the paraboloid defined by the equation \(z = x^2 + y^2\) can be determined by substituting the parametric equations into the paraboloid's equation. Specifically, substituting \(x = t\) and \(z = 2t - t^2\) leads to the equation \(2t - t^2 = t^2\). Solving this results in the intersection points at \(t = 0\) and \(t = 2\), which correspond to the points \((0, 0, 0)\) and \((2, 0, 0)\) on the paraboloid.

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Homework Statement



At what point does the curve [itex]\vec{r}(t) = <t,0,2t-t^2>[/itex] intersects the paraboloid [itex]z=x^2+y^2[/itex]

Homework Equations



None Known

The Attempt at a Solution



I assume that it might be easier to parametrize [itex]z=x^2+y^2[/itex], but I'm not sure how to do that or if there's a more standard approach.

I missed a day of class and I can't find any examples more than vaguely similar to this in the book. :\


Thanks for any help!
 
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You can also try to de-parameterize ##\vec r(t)##. Hint: there won't be any y terms.
 

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