Undergrad Spatially Homogeneous Scalar Field on Spacetime: Showing $\nabla^2 f$

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For a spatially homogeneous scalar field f on the given spacetime, it is established that the Laplacian operator yields the result ∇²f = 𝑓̈ + 3H𝑓̇. The condition of spatial homogeneity implies that f is solely a function of time, eliminating spatial derivatives. The derivation involves applying the covariant Laplacian and recognizing that only time derivatives remain due to the lack of spatial dependence. The appropriate trace of the Christoffel symbols is crucial in simplifying the expression. This leads to the conclusion that the dynamics of f are governed by its time evolution and the expansion rate H.
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If ##f## is a "spatially homogeneous" scalar field on spacetime ##ds^2 = dt^2 - a^2(t) \delta_{ij} dx^i dx^j## then show that ##\nabla^2 f = \ddot{f} + 3H \dot{f}##. Should be easy if I knew what the condition on ##f## is, i.e. ##\nabla^2 f = \partial_{\mu} \partial^{\mu} f = \ddot{f}- a^{-2}(t) \delta^{ij} \partial_i \partial_j f = \dots##?
 
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Spatially homogeneous = does not depend on spatial position. In other words, ##f## is a function of ##t## only.
 
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I messed up the double covariant, should be:\begin{align*}
\nabla^2 f &= \nabla_{\mu}(\partial^{\mu} f) \\
&= \partial_{\mu} \partial^{\mu} f + g^{\nu \rho} \Gamma_{\mu \nu}^{\mu} \partial_{\rho} f \\
&= \partial_t^2 f + 3H \partial_t f
\end{align*}(##\Gamma_{0i}^{j} = H\delta^{j}_{i}##)
 
Indeed. Only the time derivatives survive since the field only depends on t. Then it is just a matter of finding the appropriate trace of Christoffel symbols.
 
MOVING CLOCKS In this section, we show that clocks moving at high speeds run slowly. We construct a clock, called a light clock, using a stick of proper lenght ##L_0##, and two mirrors. The two mirrors face each other, and a pulse of light bounces back and forth betweem them. Each time the light pulse strikes one of the mirrors, say the lower mirror, the clock is said to tick. Between successive ticks the light pulse travels a distance ##2L_0## in the proper reference of frame of the clock...

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