Special Relativity Forces and Energy

jeffbarrington
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Homework Statement


Hi, I have this problem:

For motion under a pure (rest mass preserving) inverse square law force f = −αr/r3 , where α is a constant, derive the energy equation γmc2 − α/r = constant.

Homework Equations


E = γmc2
dE/dt = f.u for a pure force

The Attempt at a Solution


I start by saying:

dE/dt = f.u = f.dr/dt

Next, I know f is independent of time, so I can just integrate this to get:

E = f.r +constant

So then you get:

γmc2 = -α/r + constant

Which is painfully close to the result I'm meant to get but out by a minus sign. I don't know if I've made an error here or if the question is erroneous.

Thanks for any help.
 
on Phys.org
Looks like there's some symbol-related confusion here.
You have 2 different variables both named "E".
 
DuckAmuck said:
Looks like there's some symbol-related confusion here.
You have 2 different variables both named "E".
Really? I don't understand how that's the case, they're both the particle's energy.

edit - I actually get something viable by considering dE/dt = grad(E) dot dr/dt, since r is a function of time and I forgot to chain rule it.
 
Last edited:

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