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Special Relativity, please explain the meaning of this problem

  1. Jan 20, 2009 #1
    The problem statement, all variables and given/known data
    The reference frame K' moves in the positive direction of the x-axis of the frame K with a relative velocity V. Suppose that at the moment when the origins of coordinates O and O' coincide, the clock readings at these points are equal to zero in both frames. Find the displacement velocity v of the point (in the frame K) at which the readings of the clocks of both reference frames will be permanently identical. Demonstrate that v<V.

    The meaning of the problem
    Ok, the problem is that I don't understand the meaning of the problem. Does it mean to find the velocity of a point (v) such that the clocks infront of each other in that point's frame show same time, but that seems me impossible, if not then what the problem may mean.
    I only want to know the meaning of the problem, please don't solve it.

    Problem is 1.355 from "Problems in General Physics - I. E. Irodov". And answer is v = (1-(1-(V/c)2)1/2)c2/V
  2. jcsd
  3. Jan 20, 2009 #2


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    Homework Helper

    I think it means that you need to find the speed of an observer, relative to K, at which the observer would calculate the clock rates in K and K' to be the same.
  4. Jan 21, 2009 #3
    Yup, thnx turin, that is what it meant.
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