Specific heat at constant pressure formula help

Click For Summary
SUMMARY

The discussion focuses on the application of the specific heat at constant pressure (Cp) and its relationship with enthalpy in thermodynamic systems where pressure varies. Participants clarify that for ideal gases, enthalpy remains independent of pressure, and the first law of thermodynamics necessitates the use of enthalpy in open systems. The use of Cp is justified as it allows for tracing changes in enthalpy, even when pressure is not constant throughout the system.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with the concept of enthalpy
  • Knowledge of ideal gas behavior
  • Basic principles of thermodynamics
NEXT STEPS
  • Study the relationship between enthalpy and specific heat in thermodynamic processes
  • Learn about the application of the first law of thermodynamics in open systems
  • Explore the properties of ideal gases and their implications in thermodynamics
  • Investigate the role of Cp in calculating changes in enthalpy
USEFUL FOR

Students of thermodynamics, engineers working with heat transfer, and anyone seeking to deepen their understanding of enthalpy and specific heat in varying pressure systems.

yecko
Gold Member
Messages
275
Reaction score
15

Homework Statement


f2vSXtq.png

https://i.imgur.com/f2vSXtq.png

Homework Equations


Kjy1Tzh.png

https://i.imgur.com/Kjy1Tzh.png

The Attempt at a Solution


In this question, the pressure is different at different point, in other words it is not constant throughout the system. Why the solution use c(p) (or "enthalpy" h which specified for constant pressure system) as part of the formula used?

Thank you very much!
 
Physics news on Phys.org
yecko said:

Homework Statement


View attachment 211514
https://i.imgur.com/f2vSXtq.png

Homework Equations


View attachment 211515
https://i.imgur.com/Kjy1Tzh.png

The Attempt at a Solution


In this question, the pressure is different at different point, in other words it is not constant throughout the system. Why the solution use c(p) (or "enthalpy" h which specified for constant pressure system) as part of the formula used?

Thank you very much!
For an ideal gas, enthalpy is independent of pressure. Doesn't the open system version of the first law require you to use enthalpy?
 
Chestermiller said:
For an ideal gas, enthalpy is independent of pressure. Doesn't the open system version of the first law require you to use enthalpy?
Is that imply enthalpy is used just because the first law of thermodynamics is applicable?
And using Cp is not contradict to the situation of pressure changed, but rather Cp is used because it can trace out the enthalpy?
Thank you very much!
 
yecko said:
Is that imply enthalpy is used just because the first law of thermodynamics is applicable?

Yes. The open system version of the first law tells us that, for your problem the change in enthalpy is equal to the change in kinetic energy.
And using Cp is not contradict to the situation of pressure changed, but rather Cp is used because it can trace out the enthalpy?
Thank you very much!
Yes.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
Replies
1
Views
2K
Replies
16
Views
4K
Replies
8
Views
2K
Replies
1
Views
2K
Replies
6
Views
2K
Replies
11
Views
2K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
7K