Specific Heat Capacity Experiment

Click For Summary

Homework Help Overview

The discussion revolves around an experiment to determine the temperature of a flame from the heat transfer between an aluminum block and water. The original poster describes the setup involving a known mass of aluminum and water at specific temperatures, aiming to find the initial temperature of the aluminum block and subsequently the flame temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the initial temperature of the aluminum block using heat transfer principles, questioning how to relate this to the flame temperature. Participants discuss the assumptions regarding heat transfer and equilibrium.

Discussion Status

Participants are exploring the relationship between the temperatures of the aluminum block and the flame, with some suggesting that the flame temperature is likely higher than the aluminum's initial temperature. There is acknowledgment of the experiment's purpose being more about learning the process rather than achieving precise results.

Contextual Notes

Some participants note the potential impact of water evaporation during the experiment, which could affect the results. The original poster emphasizes that the focus is on understanding the experiment and calculations rather than obtaining an exact flame temperature.

Peter G.
Messages
439
Reaction score
0
So our teacher wants us to find the temperature of a flame of a bunsen burner. To do so, he told us to do the following:

Heat an aluminium block of known mass (160g), but unknown initial temperature.

Drop it in a beaker with 500 ml of water, of known temperature (22 degrees) and let the aluminium block lose heat to the water. When the temperature stabilizes, (33 degrees), that is when the system is in equilibrium, so both the water and the aluminium block are at the same temperature.

He also gave us the values of Specific Heat Capacity of water and aluminium.

How can I obtain the temperature of the flame from this? All I tried doing was:

First of all: 1 ml of water = 500 g of mass, 0.5 kg.

The heat energy the water gained to change temperature is equal to the heat energy lost by the aluminium block, hence:

Q = 4200 x 0.5 x 11
=23100 J

From this we can work out the initial temperature of the block, before being thrown in water:

23100 = 880 x 0.16 x (vi)- 33)
164.0625 = vi - 33
vi = 197.1 Degrees celsius

But, how do I go from there to find the temperature of the flame? Any help?

Thanks,
Peter G.
 
Physics news on Phys.org
Hi Peter,

I think you have found what your teacher expected. The temperature of the flame will likely be higher than the initial temp of the aluminum for various reasons, especially if the flame did not envelope all of the aluminum, but you have no information enabling you to get a better estimate.
 
Ok Delphi, so, in a case like this, the temperature of the flame should "equal" the temperature of the block for the same reason the block and water eventually go into equilibrium?

Heat is being transferred from the substance with the most energy to the one with the least?
 
Last edited:
Right. Better to say temperature instead of energy in the last sentence.
 
Did you lose much water to evaporation when you dropped the hot aluminum block into the beaker?
 
Hi. Thanks for the answers.

Olivermsun, yes I did but we discussed that beforehand. The purpose of the experiment was not to try and get as close as possible to the correct temperature of the flame but to learn how to perform the experiment and, more importantly, the calculations.
 
Ah. Gotcha. :)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
963
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
16K
Replies
54
Views
9K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K