Specific Heat Problem and boiling water

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The discussion revolves around a specific heat problem involving boiling water and an aluminum pan. The user sets up the equation Q=mcΔT to calculate the final temperature after mixing 140 grams of boiling water at 100°C with an aluminum pan at 24°C. The calculations lead to a final temperature of approximately 52.319°C. Clarification is provided that this value represents the final temperature, not the temperature change. The conversation confirms the accuracy of the calculations and understanding of the concept.
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Homework Statement


140 grams of boiling water (temperature 100° C, heat capacity 4.2 J/gram/K) are poured into an aluminum pan whose mass is 1100 grams and initial temperature 24° C (the heat capacity of aluminum is 0.9 J/gram/K).
After a short time, what is the temperature of the water?


Homework Equations


Q=mc delta t


The Attempt at a Solution



140g(4.2J/K/gram)(T-100) = 1100g(0.9 J/K/gram)(24-T)
588T-58800 = 23760 - 990 T
588T + 990 T = 23760 + 58800
1578 T = 82560
T= 52.319

Am I doing this right?
 
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Looks good to me, clutch.
 
Alright and when I am determining the temperature am i subtracting 100-52.319 or no?
 
No, 52.319 is the final answer. 100-52.319 would be the change in temperature of the water.
 
oh ok thanks for clearing that up
 

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