- #1

clutch12

- 21

- 0

## Homework Statement

140 grams of boiling water (temperature 100° C, heat capacity 4.2 J/gram/K) are poured into an aluminum pan whose mass is 1100 grams and initial temperature 24° C (the heat capacity of aluminum is 0.9 J/gram/K).

After a short time, what is the temperature of the water?

## Homework Equations

Q=mc delta t

## The Attempt at a Solution

140g(4.2J/K/gram)(T-100) = 1100g(0.9 J/K/gram)(24-T)

588T-58800 = 23760 - 990 T

588T + 990 T = 23760 + 58800

1578 T = 82560

T= 52.319

Am I doing this right?