Specific Heat Problem in Celsius

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SUMMARY

The specific heat of substance X is established at 200 J/g°C. To calculate the heat required to raise the temperature of 2.0 kilograms of substance X from 40 degrees Celsius to 55 degrees Celsius, the formula Q=(m)(c)(ΔT) is applied. The temperature change (ΔT) is 15°C, and the mass is converted to grams (2000 g). The total heat required is calculated as 6,000,000 J, confirming the accuracy of the solution presented.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula Q=(m)(c)(ΔT)
  • Ability to convert kilograms to grams
  • Knowledge of temperature measurement in Celsius
NEXT STEPS
  • Study the concept of specific heat capacity in detail
  • Learn about heat transfer and its applications in thermodynamics
  • Explore significant figures and their importance in scientific calculations
  • Investigate other materials' specific heat values for comparative analysis
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Students studying thermodynamics, physics enthusiasts, and anyone involved in heat transfer calculations will benefit from this discussion.

Ki-nana18
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Homework Statement



The specific heat of substance X is 200 J/g*C, how much heat is required to change the temperature of 2.0 kilograms of substance X from 40 degrees Celsius to 55 degrees Celsius?

Homework Equations



Q=(m)(c)(change T)

The Attempt at a Solution


55 C-40 C= 15 C
2.0kg(1000 g/1 kg)= 2000 g

(2000 g)(200 J/g*C)(15 C)= 6000000 J

I'm am not sure if this is right at all. :rolleyes: Is it right?
 
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Looks correct to me.
 
Watch significant numbers.

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methods
 

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