Specific Heat (The Very Concept)

Click For Summary
SUMMARY

The discussion centers on the concept of specific heat, defined as the ratio of heat required to raise the temperature of a unit of substance by one degree compared to the heat required for the same unit of water. A specific example involves a 50-lb ball of iron with a specific heat of 0.11, illustrating that it requires only 0.11 times the heat needed for an equivalent mass of water to achieve the same temperature increase. This clarification resolves confusion regarding the calculation of total heat, emphasizing the importance of the specific heat ratio in thermodynamics.

PREREQUISITES
  • Understanding of basic thermodynamic concepts
  • Familiarity with the definition of specific heat
  • Basic knowledge of units of mass and temperature
  • Ability to perform simple mathematical calculations involving ratios
NEXT STEPS
  • Study the principles of thermodynamics, focusing on heat transfer
  • Learn about specific heat capacities of various materials
  • Explore the concept of calorimetry and its applications
  • Investigate the relationship between mass, temperature change, and heat energy
USEFUL FOR

Students in physics or engineering, educators teaching thermodynamics, and anyone seeking to understand heat transfer principles and specific heat calculations.

aleph_0
Messages
6
Reaction score
0
So I don't get the concept of specific heat. I'm doing an ODE problem and I've never even looked at science, not even in high school. The book defines the specific heat of a substance as: The ratio of the quantity of heat required to raise the temperature of a unit of substance by one degree, to the quantity of heat required to raise the same unit of water by one degree.

Now take for instance a 50-lbs ball of iron heated to 200 degrees, where iron has a specific heat of .11. A priori I would have thought that the total quantity of heat would be 50(200) because, hey, temperature is like average quantity of heat in an object, right? And the object weighs 50-lbs, which can basically be treated like its mass. So the product should give the total heat, no? Huh? Right?

Well I would be wrong. It looks like the quantity of heat in such an object is 50(.11)(200) and I don't exactly get why. What in god's name does that ratio have to do with this sort of thing?

Thank you.
 
Science news on Phys.org
welcome to pf!

hi aleph_0! welcome to pf! :smile:

it means that if you need X amount of heat to raise 50-lbs of water by 200°, then you only need 0.11 times X to raise 50-lbs of iron by 200° :wink:
 
OH MY GOD that was the perfect answer! So clear, so simple. THANK YOU!

(Part of this is general excitement about learning a concept; the other part is too much coffee.)
 

Similar threads

  • · Replies 66 ·
3
Replies
66
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
843
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K