Speed of a proton through potential difference

[cookiemnstr510510]

Homework Statement

What is the speed of a proton that has been accelerated from rest through a potential difference of -1000V?

Homework Equations

ΔV=potential difference
V=U/q
Conservataion of energy
U=qEd (d is distance the proton is moving...i think)

The Attempt at a Solution

Here is my thought process with this problem:
ΔV=-1000V this means the change in electric potential is (-), doesn't tell us what V(initial) or V(final) is, but we know the difference between them is 1000
I know that V=U/q
For the proton going through this potential difference it follows conservation of energy:
K_i+U_i=K_f+U_f→0+qEd=1/2m_pv²+0→qEd=1/2m_pv²
here is where I get stuck...
it looks to me like we have one equation and two unknowns
the equation being:qEd=1/2m_pv²
the unknowns: E and v
And I guess I am not even sure if U_f=0.

 

[berkeman]

Are you familiar with the conversion between eV and Joules? And in problems like this, usually you would assume the particle starts at rest, unless stated otherwise.

 

[Orodruin]

You do not need E or d, you were given the potential difference.

 

[cookiemnstr510510]

Are you familiar with the conversion between eV and Joules? And in problems like this, usually you would assume the particle starts at rest, unless stated otherwise.

I am not familiar with this.

 

[cookiemnstr510510]

You do not need E or d, you were given the potential difference.

So we can then say ΔV=U/q=qEd/q=Ed? that's all I am seeing from this. There may be another equation I am not remembering that relates potential difference to potential energy...

ahh, are you saying that ΔV=U/q can be solved so U=qΔV and in this case everything is known?
then the equation:
K_i+U_i=K_f+U_f→0+U_i=(1/2)mv²+0→qΔV=(1/2)mv² and then we can solve for v? That makes sense

 

[Orodruin]

So we can then say ΔV=U/q=qEd/q=Ed?

You really cannot because nowhere in the problem is it stated that there is a constant field. You are just complicating your life by introducibg it at all. The first equality is all you need and all you can really say based on the provided information.

 

[cookiemnstr510510]

You really cannot because nowhere in the problem is it stated that there is a constant field. You are just complicating your life by introducibg it at all. The first equality is all you need and all you can really say based on the provided information.

the first equality being ΔV=U/q?