Speed of an electron and potential difference

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Homework Help Overview

The discussion revolves around the effects of a potential difference applied to a stationary electron, specifically focusing on calculating the electron's final speed using relativistic formulas. Participants explore the relationship between kinetic energy, total energy, and mass energy in the context of relativistic physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of relativistic formulas to find the final speed of an electron after being accelerated by a potential difference. Questions arise regarding the appropriate values for energy and the definitions of kinetic energy in this context.

Discussion Status

The conversation is ongoing, with participants providing insights into the calculations involved and the conditions under which relativistic effects become significant. Some participants have offered formulas and clarifications, while others are questioning the assumptions and definitions being used.

Contextual Notes

There is a mention of the threshold for using relativistic formulas, specifically when kinetic energy approaches 10% or more of the rest mass energy of the electron. Additionally, the distinction between classical and relativistic mechanics is being examined, particularly at high speeds.

grscott_2000
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I have a question here where a potential difference is applied to a stationary electron. I have calculated the energy translated to the electron already and I know the mass energy of the electron.

If I want to find its final speed I assume that I use a rearrangement of the relativistic formula? And if so, what value would I use for Energy? Would it simply be the total energy : mass energy + translated energy?

Thanks for any help
 
Last edited:
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grscott_2000 said:
I have a question here where a potential difference is applied to a stationary electron. I have calculated the energy translated to the electron already and I know the mass energy of the electron.

If I want to find its final speed I assume that I use a rearrangement of the relativistic formula? And if so, what value would I use for Energy? Would it simply be the total energy : mass energy + translated energy?

Thanks for any help


There are many formulas you can use,

E_{tot} = E_{k} + mc^{2} = \gamma mc^{2}

\gamma = \dfrac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

remember that you can not take the rest mass of the electron in the expression of the kinetic energy.
 
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Would that be Ek as in translated kinetic energy?
 
grscott_2000 said:
Would that be Ek as in translated kinetic energy?


Well E_k is kinetic energy, what you mean by "translated kinetic energy" I do not know.

You can also use this:


(E_tot)^2 = (pc)^2 + (mc^2)^2

where p is the momentum:
p = gamma * mv, v is velocity.

And from this we can get:

v = c * sqrt[1 - (mc^2 / E_tot)^2 ]
 
I see... So if I have calculated the kinetic energy of an electron to be for example 6 x 10^-12J, then I can calculate the total energy as

(6 x 10^-12J) + mass of electron * speed of light^2 ?

And once this is established I can use one of the formulas to give me v?
 
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How did you calculate the kinetic energy of electron?

You took:

Potential (electrical) energy = qV, where V is the electric poteintal, and then
qV = Kinetic energy?

Well then it is ok, and if you want to find out the velocity of the electron, you must calculate relativistic. (if the kinetic energy is approx 10% or more of the rest mass energy of electron)
 
yes that's exactly it... potential difference(100V) x charge of electron(q).

I understand that relativistic formulas are used when the particles speed become close to the speed of light. Is this right? Otherwise the classic Newtonian formula 1/2 mv^2 can be used?
 
grscott_2000 said:
yes that's exactly it... potential difference(100V) x charge of electron(q).

I understand that relativistic formulas are used when the particles speed become close to the speed of light. Is this right? Otherwise the classic Newtonian formula 1/2 mv^2 can be used?

yes, as I said, when the kinetic energy is apporx 10% or more, it may be good to use relativistic. The bigger the E_k is compared to the rest mass, the better to use the relativistic =)
 
Many thanks for your assistance
 
  • #10
malawi_glenn said:
yes, as I said, when the kinetic energy is apporx 10% or more, it may be good to use relativistic. The bigger the E_k is compared to the rest mass, the better to use the relativistic =)

Hi there, sorry if this sounds like a noob question but why can't you use Newtonian formula at speeds close to c :confused:
 

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