Speed of electron into electric/magnetic fields

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SUMMARY

The discussion focuses on calculating the speed of an electron moving into perpendicular electric and magnetic fields, specifically with given parameters: a voltage (V) of 2000 V, a distance (d) of 0.080 m between charged plates, and a magnetic field (B) of 0.0028 T. The electric field (E) is calculated as 25000 V/m, and the force (F) on the electron due to the electric field is determined to be 4 x 10^-15 N. The key conclusion is that for the electron to pass through both fields undeflected, the forces from the electric and magnetic fields must cancel, leading to the need for further calculations to find the required speed of the electron.

PREREQUISITES
  • Understanding of electric fields and their calculations (e.g., E = V/d)
  • Knowledge of magnetic fields and Lorentz force (F = Bqv)
  • Familiarity with the properties of electrons, including charge (q = 1.60 x 10^-19 C)
  • Basic algebra and physics problem-solving skills
NEXT STEPS
  • Calculate the speed of the electron using the equation for force balance: F_electric = F_magnetic
  • Explore the implications of undeflected motion in electric and magnetic fields
  • Review the concepts of electric field strength and magnetic field strength in particle physics
  • Investigate the applications of charged particles in electric and magnetic fields in technology
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, as well as educators seeking to clarify concepts related to charged particles in electric and magnetic fields.

shanktank
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attached is my attempt to answer part b) of this question. I have been told its wrong but don't know what I'm missing, any ideas?
 

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sorry the image didn't show up like planned i'll type it out.

b) Calculate the speed of the electron moving into the electric and magnetic fields...

we have a diagram in part a) that shows an electron moving into the plane of the page.

were given:
V = 2000 V between charged plates
d= 0.080 m between charged plates
B = 0.0028 T

The electron enters the electric field, which is perpendicular to the magnetic field, and passes through both fields undeflected.


Here now is my attempt at an answer.

V=2000 V
d= 0.080 m
B = 0.0028 T
q = 1.60 x 10^-19 C

E = F/d E = 2000 V / 0.080 m = 25000 V/m

F= Bqvelocity

F= Eq
(25000V/m)(1.60 x 10^-19)
= 4 x 10^-15 N
 
I can't see the image yet, so correct me if I'm wrong about what's going on.

What have you done with the magnetic field in your calculation? If the electron passes undeflected, that means the force from the electric field and the force from the magnetic field must cancel out. So at what speed does that happen? I think you have started out OK, you just need to finish. Why is your work considered wrong?
 

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