Sphere equation from endpoints.

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Homework Help Overview

The discussion revolves around finding the equation of a sphere given the endpoints of one of its diameters, specifically the points (-19, -15, -3) and (1, 5, 17).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the sphere's equation by calculating the midpoint and the distance to one endpoint, but indicates that their result is incorrect. Some participants suggest verifying the radius calculation and show concern regarding the method used to derive the radius from the diameter.

Discussion Status

Participants are actively engaging with the problem, offering suggestions to check calculations and clarify methods. There is a collaborative effort to identify where the original poster's approach may have gone awry, particularly regarding the radius.

Contextual Notes

There is an indication that the original poster's equation was derived from their calculations, but it is noted that the program used for verification indicated an error. The discussion includes checking assumptions about the radius and the calculations leading to the sphere's equation.

graycolor
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Find the equation of a sphere if one of its diameters has endpoints: (-19, -15, -3) and (1, 5, 17).



Thought it would be this, but the program web-work says its wrong.

Lets assume my first coordinate is a (-19, -15, -3) and b is (1, 5, 17)

I found the midpoint since I assumed that would be the center, then I found the length from my midpoint to b ,but my equation is wrong.

(x+9)^2+(y+5)^2+(z-7)^2-640=0
 
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hey graycolor, method sounds right... showing your working will help finding the problem easier...

that said, I would check your radius
 
I think you calculated the radius wrong.

[tex]radius=diameter/2[/tex]

[tex]diameter=\sqrt{(-19-1)^2+(-15-5)^2+(-3-17)^2}=\sqrt{3*20^2}=20\sqrt{3}[/tex]

Now find the radius and then r2. :smile:
 
Thanks guys
 

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