Spin Angular Momentum - Bullet hitting bottom of a thin rod?

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SUMMARY

The discussion centers on the conservation of angular momentum in a system where a bullet strikes a thin rod. It is established that angular momentum is conserved due to the absence of external torques, while energy is not conserved due to the inelastic nature of the collision. Linear momentum is also not conserved because an external force acts on the rod's center of mass post-collision. The solution involves equating the initial angular momentum of the bullet and rod system with the final angular momentum to determine the angular velocity, which can then be converted to linear velocity.

PREREQUISITES
  • Understanding of angular momentum conservation principles
  • Knowledge of inelastic collisions and their effects on energy
  • Familiarity with the concept of external forces in a system
  • Basic mechanics of pendulum motion and ballistic pendulums
NEXT STEPS
  • Study the conservation of angular momentum in various collision scenarios
  • Learn about inelastic collisions and their implications on energy conservation
  • Explore the mechanics of ballistic pendulums and their applications
  • Investigate the role of gravitational acceleration (g) in pendulum motion
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Students studying physics, particularly those focusing on mechanics and conservation laws, as well as educators looking for examples of angular momentum applications in collision scenarios.

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Homework Statement



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Homework Equations





The Attempt at a Solution


Angular momentum is the only parameter conserved. This is because there are no external torques acting on the system. Energy is not conserved because the collision is inelastic. Finally, linear momentum is not conserved because there is an external force acting on the rod's center of mass that prevents the system from moving forward after the collision.

Now, for part d, I am not so sure what to do. Should I equate the angular momentum of the system before the bullet hits with the final angular momentum of the system, solve for angular velocity, and turn that into linear velocity? Though I have no idea how g would come into play..
 
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Your plan to get going is good. After the embedding of the bullet, the thing is just a kind of pendulum (a variation on the ballistic pendulum).

If you fill in the relevant equations under 2, you automatically get to see the role of g.
 

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