Splitting an integral with an absolute value

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SUMMARY

The discussion centers on the proper method to split the integral of the function \(\int_{-\infty}^{\infty}(x/x_0)e^{-2|x|/x_0} dx\) for integration. Participants clarified that the integral can be split into two parts: \(\int_{-\infty}^{0}(x/x_0)e^{2x/x_0}dx\) and \(\int_{0}^{\infty}(x/x_0)e^{-2x/x_0}dx\). It was emphasized that while one can consider doubling the integral from 0 to infinity, this approach is incorrect due to the differing behavior of the function across the negative and positive domains. Integration by parts is recommended for the evaluation.

PREREQUISITES
  • Understanding of definite integrals and improper integrals
  • Familiarity with the properties of absolute values in calculus
  • Knowledge of integration techniques, specifically integration by parts
  • Proficiency in LaTeX formatting for mathematical expressions
NEXT STEPS
  • Study the method of integration by parts in detail
  • Explore the properties of even and odd functions in relation to integrals
  • Learn how to properly format mathematical expressions using LaTeX
  • Investigate the implications of absolute values in integrals and their effects on convergence
USEFUL FOR

Students and educators in calculus, particularly those dealing with integrals involving absolute values and integration techniques. This discussion is beneficial for anyone looking to enhance their understanding of integral calculus and its applications in physics.

Koshi
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This is a physics problem, but I only need help with the calculus portion of it. I was having trouble figuring out how to split the integral to properly integrate.


Homework Statement




Homework Equations



\int\stackrel{\infty}{-\infty}(x/x_0)e-2|x|/x_0dx

where x_o is a constant

The Attempt at a Solution



I was wondering how to write the lower part of the integral. What I have is

\int\stackrel{0}{-\infty}(x/x_0)e2x/x_0dx+\int\stackrel{\infty}{0}(x/x_0)e-2x/x_0dx

Is that right or should I keep the negative in front of the 2 in the lower integral?
 
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You've got it right. But there is an easy way to do your integral. If f(x) is the integrand, how does f(x) compare with f(-x)?
 
Fixed the LaTeX in your first integral. Double-click it to see what I did.
Here are some tips:
Use only a single pair of [ tex] and [ /tex] tags (without the leading spaces that I show) for a given expression. You had tex tags around almost every item.
Don't mix [ sup] and [ sub] tags inside [ tex] tags. They don't work. Instead use ^{} for superscripts and _{} for subscripts.
Koshi said:
This is a physics problem, but I only need help with the calculus portion of it. I was having trouble figuring out how to split the integral to properly integrate.


Homework Statement




Homework Equations



\int_{-\infty}^{\infty}(x/x_0)e^{-2|x|/x_0} dx

where x_o is a constant

The Attempt at a Solution



I was wondering how to write the lower part of the integral. What I have is

\int\stackrel{0}{-\infty}(x/x_0)e2x/x_0dx+\int\stackrel{\infty}{0}(x/x_0)e-2x/x_0dx

Is that right or should I keep the negative in front of the 2 in the lower integral?
 
Mark44 said:
Fixed the LaTeX in your first integral. Double-click it to see what I did.

Thanks for the fix. I was struggling with it :P
 
Dick said:
You've got it right. But there is an easy way to do your integral. If f(x) is the integrand, how does f(x) compare with f(-x)?

I was thinking I could just double the integral from 0 to \infty but because there was an x/x_0 in front and I would have to integrate by parts, I reasoned against it.

I wouldn't know how else to simplify it.
 
Koshi said:
I was thinking I could just double the integral from 0 to \infty but because there was an x/x_0 in front and I would have to integrate by parts, I reasoned against it.

I wouldn't know how else to simplify it.

Yes, if you want to do the integral from 0 to infinity you should integrate by parts. But you can't double it to get the whole integral because the integral from -infinity to 0 isn't the same. How are the two integrals related? You could, of course, just do the integration and find out... But you would be going to a lot of extra work.
 

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